Answer:
(a) 1, 2, 3, 6, 8
Explanation:
Given


Required
The sequence of hours worked each day
See attachment for options
From the question, we understand that:

This means that, the middle number is 3 (when sorted)
So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively
Next, is to determine the mean of (a) and (d)
The mean of a data is calculated as:

So, we have:
(a)



(d)



Option (a) is true, because it has:

