Question

A 15kg dog jumps out of a 40 kg canoe. If the dog's velocity is 1.2 m/s, what is the velocity of the canoe

Answer 1

the velocity is 0.45 m/s and it is moving in the opposite direction

or

-0.45 m/s

Step-by-step explanation:

The law of conservation of momentum says that initial momentum = final momentum

( mass x velocity of the dog ) = - (mass x velocity of the canoe)

(15 x 1.2) =- (40 x velocity of the canoe)

Velocity of the canoe = -(15 x 1.2) / 40 = -0.45 m/s