Question

A 50,000 g septic tank reading reports that methane gas bubbles are present with a concentration of 17 ppm

Answer 1

`m_(solute)=0.85g`

Step-by-step explanation:

Hello there!

In this case, according to the given information for the parts per million of methane in this solution, it is possible for us to first write the equation for this unit of concentration as shown below:

`ppm=(m_(solute))/(m_(solvent)) *1x10^6`

In such a way, since the septic tank has a mass of 50,000 g, the mass of methane into it is calculated as shown below:

`m_(solute)=(ppm*m_(solvent))/(1x10^6)`

Now, we plug in the numbers to obtain:

`m_(solute)=(17*50000g)/(1x10^6)\\\\m_(solute)=0.85g`

Regards!