Question

URGENT A person was standing on top of an office building and ‘accidentally' dropped a rock off the roof . How tall is the building if the total velocity is 123m/s and the horizontal velocity is 22m/s?

Answer 1

Building is 747.19 m tall

Step-by-step explanation:

Given, t

Total velocity v = 123 m/s

Horizontal velocity or the X -component if velocity vx = 22 m/s

For a horizontal projectile motion

V = Sqrt (vx^2 + g^2t^2)

Or t = sqrt{(v^2 – vx^2)/g^2} ---Eq (1)

Time of flight

t = sqrt (2h/g) – Eq (2)

where h is the height

Equating, both the equation, we get –

h = (123^2 – 22^2)/19.6 = 747.19 m