Question

1.00 mole of an ideal gas occupies a volume of 22.4 L at 0 C and 760 mmHg (STP). It is cooled to -41 C while the pressure is increased to 805 mmHg. What is the new volume of the gas in liters?

Answer 1

`V_2=18.0L`

Step-by-step explanation:

Hello there!

In this case, according to the given information, we infer that we need the combined gas law in order to solve this problem:

`(P_2V_2)/(T_2)} =(P_1V_1)/(T_1)}`

Thus, by suing the temperatures in Kelvins, we can solve for the final volume as shown below:

`V_2 =(P_1V_1T_2)/(T_1P_2)}\\\\V_2 =((760mmHg)(22.4L)(232K))/((273K)(805mmHg)) \\\\V_2=18.0L`

Regards!