Question

You choose a tile at random from a bag containing 4 A's, 3 B's, and 5 C's. You dep place the first tile and then choose again. Find P (B and B)

Answer 1

1 /16

Explanation:

Tiles in bag :

4 A's, 3 B's, and 5 C's.

Total = (4 + 3 + 5) = 12

Probability B = required outcome / total possible outcomes

P(picking B) = number of B / total tiles

P(B) = 3 /12 = 1/4

With replacement :

Picking a second B;

P(picking B) = 3 /12 = 1/4

Hence,

P(B and B) = 1/4 * 1/4 = 1/16