Question

The speed of light in a piece of plastic is 1.87 × 10^8 meters per second. What is the absolute index of refraction of this plastic?

options:
1.0
1.6
0.67
1.33

Answer 1

n = 1.6

Step-by-step explanation:

The formula for the calculation of the absolute index of refraction is given as follows:

`n = (c)/(v)`

where,

n = index of refraction

c = speed of light in vacuum = 3 x 10⁸ m/s

v = speed of light in the piece of plastic = 1.87 x 10⁸ m/s

Therefore,

`n = (3\ x\ 10^8\ m/s)/(1.87\ x\ 10^8\ m/s)`

n = 1.6