Given:
The sequence is:
![16,80,400,...](https://img.qammunity.org/2022/formulas/mathematics/high-school/4u06oonupqk9b7ytqrpwqamh05liibsps1.png)
To find:
The 6th term of the given sequence.
Solution:
We have,
![16,80,400,...](https://img.qammunity.org/2022/formulas/mathematics/high-school/4u06oonupqk9b7ytqrpwqamh05liibsps1.png)
Here, the first term is:
![a=16](https://img.qammunity.org/2022/formulas/mathematics/high-school/4mr5hfg3v9pe4vl9z9wd33h28hqrzbf2ww.png)
The ratio between consecutive terms are:
![(80)/(16)=5](https://img.qammunity.org/2022/formulas/mathematics/high-school/4j34iqbsjroofpwmf7ze9kq3fzmzciy011.png)
![(400)/(80)=5](https://img.qammunity.org/2022/formulas/mathematics/high-school/gbcwdiovch7mx8t448z6j6yrcdihk4t7i8.png)
The given sequence has a common ratio 5. So, the given sequence is a geometric sequence.
The nth term of a geometric sequence is:
![a_n=a(r)^(n-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/yyvbue65rag19mdvh344axy0vy0nqvrgy0.png)
Where, a is the first term and r is the common ratio.
Substitute
to get the 6th term.
![a_6=16(5)^(6-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/fjiljd0l78he2oubz7p90oj0msba16y249.png)
![a_6=16(5)^(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/w09wy8hmhssy6jcsa2viqmhvywxmapnpd2.png)
![a_6=16(3125)](https://img.qammunity.org/2022/formulas/mathematics/high-school/6uf2d12oql18ql3h6ar5fyhsrhm5j8l60h.png)
![a_6=50000](https://img.qammunity.org/2022/formulas/mathematics/high-school/mdub90885pmjc1tg1o7gf5f91ynyzthtx5.png)
Therefore, the 6th term of the given sequence is 50000.