Question

2. If I have 7.70 moles of gas at a pressure of 202.6 kPa, and a temperature of 59.0°C, what is the

volume of the container that the gas is in?

Answer 1

V = 0.104 m³

Step-by-step explanation:

Given that,

Number of moles, n = 7.70 moles

Pressure, P = 202.6 kPa

Temperature, T = 59.0°C = 332 K

We need to find the volume of the container that the gas. We know that the ideal gas law is as follows :

`PV=nRT\\\\V=(nRT)/(P)`, R =8.314 m³-Pa/K-mol

Put all the values,

`V=(7.7* 8.314* 332)/(202.6 * 10^3)\\\\V=0.104\ m^3`

So, the volume of the container is equal to 0.104 m³.