Question

If 0.142857142857......is expressed in the form m/n, then what is the value
of (2m + n)?​

Answer 1

The value will be: 1,285,713

Explanation:

We have the number:

N = 0.142857...

Such that we have 6 decimals after the decimal point that repeat infinitely.

Then let's start by multiplying our number by 1,000,000 (same number of zeros as decimals after the decimal point)

Then we get:

1,000,000*N = 142,857.142857...

Now let's subtract N from both sides:

1,000,000*N - N = 142,857.142857... - 0.142857...

999,999*N = 142,857

Now let's isolate N

N = 142,857/999,999

Here is our number expressed in the form m/n, where:

m = 142,857

n = 999,999

Then the value of (2*m + n) is:

(2*142,857 + 999,999) = 1,285,713