Let the consecutive integers be x and x+1.
Then,
x + (x + 1) = 23
=> x + x + 1 = 23
=> 2x + 1 = 23
=> 2x = 23 - 1
=> 2x = 22
=> x = 22/2
=> x = 11
So, the integers are:
x = 11
and x + 1 = 11 + 1 = 12
So, the consecutive integers are 11 and 12.
4.6m questions
6.0m answers