Question

The specific heat of water is 4.184 J/g·K. How much energy must be added to 100.0 g of water to raise the temperature of water from 22.0 ºC to 90.0 ºC?

Answer 1

Using the formula q = mcΔT, it is calculated that 28,452.8 joules of energy is needed to raise the temperature of 100.0 g of water from 22.0 ºC to 90.0 ºC.

Step-by-step explanation:

To calculate the amount of energy required to raise the temperature of water from 22.0 ºC to 90.0 ºC, we can use the formula: q = mcΔT, where ‘q’ is the heat energy, ‘m’ is the mass of the water, ‘c’ is the specific heat capacity, and ΔT is the change in temperature.

For this question, we have:

• m = 100.0 g (mass of the water)
• c = 4.184 J/g·K (specific heat capacity of water)
• ΔT = 90.0 ºC - 22.0 ºC = 68.0 ºC (temperature change)

Plugging these values into the formula gives us:

q = (100.0 g) × (4.184 J/g·K) × (68.0 K) = 28452.8 J

Therefore, 28,452.8 joules of energy must be added to the water.