Question

A helium-filled balloon contains 0.16 mol He at 101 kPa and a temperature of 23°C. What is

the volume of the gas in the balloon?

Answer 1

V = 3.9 L

Step-by-step explanation:

Given:

T = 23°C + 273 = 296K

n = 0.16 mol He

P = 101 kPa = 0.997 atm

R = universal gas constant = 0.08205 L-atm/mol-K

V = ?

Using the ideal gas law,

PV = nRT

V = nRT/P

= (0.16 mil He)(0.08205 L-atm/mol-K)(296K)/(0.997 atm)

= 3.9 L