20, 21, 22
Explanation:
Let x = the smallest integer of the three consecutive ones
(x + 1) = the next consecutive integer after x
(x + 2) = the next consecutive integer after (x + 1)
The sum of these three should add up to 63 so
x + (x + 1) + (x + 2) = 63
This simplifies to
3x + 3 = 63
Solving for x, we get
x = 20
Therefore, the three consecutive integers whose sum add up to 63 are 20, 21 and 22.