Hey there! I'll try to provide you with my best answer.
Answer: 21710 J
You need to quote the latent heat of fusion of water first which is 3.34 * 10^5 J/kg.
So to do this you can use the formula:
Heat required= Latent heat of fusion * mass (must be in kg)
The question asks for how much heat is needed so we will find heat required. We must also know the latent heat of fusion of the liquid that is to be melt. In this case, it is water so the latent heat of fusion of water is 3.34*10^5 J/kg. And the mass of water is 65 grams. When converted to kg it is 0.065 kg. Now place the values according to the formula.
Heat required= 3.34 * 10^5 * 0.065
= 21710
So, 21710 joules of heat is needed to change 65 grams of ice to melt into water at 0ºC
Note: Both the ice and the water are assumed to be at 0° C of course, if different temperatures are specified you will need the heat capacities of ice, and of liquid water.
Sorry for making it too long. And hope it helped!! ^^