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Give the following number of protons, neutrons, and electrons in the following isotope:

ll5Ag

Group of answer choices

47,47.64

47,47.68

47,47.47

User Stb
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1 Answer

3 votes

Answer:

47, 68, 47

Step-by-step explanation:

Let's consider the following isotope: ¹¹⁵Ag.

If we look in the Periodic Table, the atomic number of Ag is 47, that is, silver has 47 protons.

Since ¹¹⁵Ag is neutral it must have the same number of protons that of electrons. Then, it also has 47 electrons.

The number 115 in ¹¹⁵Ag stands for the mass number, which is the sum of protons and neutrons. Then, the number of neutrons is:

p⁺ + n⁰ = 115

n⁰ = 115 - p⁺ = 115 - 47 = 68

The number of protons, neutrons, and electrons in ¹¹⁵Ag is: 47, 68, 47.

User Markokstate
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