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Find cotθ if θ terminates in Quadrant III and secθ = 2

a. - (sqrt 3)/3
b. (sqrt 3)/3
c. - sqrt 3
d. sqrt 3

1 Answer

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Answer:

we have

secθ = 2


(1)/(cos θ)=2

Cosθ =
(1)/(2 )


(b)/(h )=(1)/(2 )

b=1

h=2

p=
√(2²-1) = √(3)

again

Cot θ=
(b)/(p )

Cot θ=
(1)/( √(3))

Cot θ=
(√(3))/(3)

It lies in Quadrant III cot is positive

Cot θ=
(√(3))/(3)

b. (sqrt 3)/3

User MisterButter
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