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In a reacting flask, 500 cm3 hydrogen is mixed with 500 cm3 oxygen and is ignited. (a) Which reactant is the limiting reagent? (b) Calculate the mass of water formed.

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Answer:

See Explanation

Step-by-step explanation:

From Gay-Lussac's law of combining volumes;

Equation of the reaction; 2H2(g) + O2(g) -------> 2H2O(g)

Ratio of volumes; 2 : 1 : 2

Initial volumes; 500cm^3 500cm^3 0 cm^3

Reacting volumes; 500cm^3 250cm^3 500cm^3

Final Volumes; 0 cm^3 250 cm^3 500 cm^3

We can easily see from the table that the limiting reactant is oxygen.

Hence, the mass of water formed is obtained from;

1 mole of gaseous water occupies 22400 cm^3

x moles of water occupies 500cm^3

x = 500cm^3 * 1 mole/22400 cm^3

x = 0.022 moles of water

Mass of water = 0.022 moles of water * 18 g/mol

Mass of water = 0.396 g

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