Question

If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?

Answer 1

5.25 moles.

Step-by-step explanation:

The decomposition reaction of NaN₃ is as follows :

`2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)`

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give
`(3)/(2)* 3.5=5.25` moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.