Answer:
c. H2(g) + CuO(s) → Cu(s) + H2O(l)
e. H2(g) + Cl2(g) → 2HCl(g)
Step-by-step explanation:
A redox reaction is a reaction that involves a changes in oxidation number of the species involved in the reaction.
The oxidizing agent experiences a decrease in oxidation number while the reducing agent experiences an increase in oxidation number.
For H2(g) + CuO(s) → Cu(s) + H2O(l)
Copper is reduced from +2 to 0 while hydrogen is oxidized from 0 to +2 Hence hydrogen is the reducing agent while copper is the oxidizing agent.
For H2(g) + Cl2(g) → 2HCl(g)
Chlorine is reduced from 0 to -1 while hydrogen is oxidized from 0 to +1. Hence chlorine is the oxidizing agent while hydrogen is the reducing agent.