Question

What is the molality of an acetic acid solution that contains 0.500 mol of HC2H3O2 (molar mass: 60g/mol) in 0.800 kg of water?

Answer 1

Answer: The molality of given acetic acid solution is 0.625 m.

Step-by-step explanation:

Given: Moles of solute = 0.5 mol

Mass of solvent = 0.8 kg

Molality is the number of moles of solute present in a kg of solvent.

Therefore, molality of the given solution is calculated as follows.

`Molality = (moles)/(mass of solvent)`

Substitute the values into above formula as follows.

`Molality = (moles)/(mass of solvent)\\= (0.5 mol)/(0.8 kg)\\= 0.625 m`

Thus, we can conclude that the molality of given acetic acid solution is 0.625 m.