Answer:
2.
Given:
m arc WXY=2×99°=198°[central angle is equal to the twice of its inscribed angle]
4.Arc CLE =2x< CDE = 2×97° = 194°[central angle is equal to the twice of its inscribed angle]
again
Arc DE =360° -72° -194° = 94°[from complete turn]
and
angle C =½ (arc DE +arc EL) =½ (94° +104°) = 99°
6) angle C =½ (360° -arc EC -arc CD)
=½ (360° -71° -109°)= 90°