Question

If p is inversely proportional to the square of q, and p is 16 when q is 11, determine p

when q is equal to 4.

Answer 1

p= 121

Explanation:

p
`\alpha`
`(1)/(q^(2) )`

p=k/
`q^(2)`

k=p
`q^(2)`

Get the value of your constant k

k=(16)(
`11^(2)`)

k= 1936

p=
`(1936)/(q^(2) )`

When q=4

p=
`(1936)/(4^(2) )`

p= 121

Answer 2

p = 121

Explanation:

inveresly proportional

pq² = k

find k the constant of proportionality

p is 16 when q is 11,

16 * 11² = k

k = 1,936

----------------------------

pq² = 1,936

determine p when q is equal to 4.

p * 4² = 1,936

16p = 1,936

p = 1,936/16

p = 121