Question

How many hydrogen atoms are present in 3.42 kg of C3H7NH2(l)?

Answer 1

Step-by-step explanation:

From the given information:

mass = 3.42 kg = 3420 g

molar mass of
`C_3H_7NH_2` = 59 g

Number of moles of
`C_3H_7NH_2 = (mass (in gram) )/(molar mass)`

Number of moles of
`C_3H_7NH_2 = (3420 \ g )/(59 \ g)`

= 57.966

number of hydrogen atoms present =
`n * N_A`

where;

`N_A = avogadro's \ constant = 6.022 * 10^(23)`

number of hydrogen atoms present
`=9 * 57.966 \imes 6.022 * 10^(23)`

`\mathbf{= 3.14 * 10^(26)}`