Question

A rectangle has the perimeter of 116 cm and its length is 1cm more than twice its width​

Answer 1

Find the dimensions of a rectangle given that its perimeter is 116

cm and its length is 1

cm more than twice its width.

Set up your solution using the variables L

for the length, W

for the width, and P

for the perimeter.

Part a: Using the definition of perimeter, what is an equation for P

in terms of L

and W

.

Part b: You also have to write an equation for L in terms of W

in terms of W

.

Solve the equations from parts a and b.

Part c: The length is cm.

Part d: The width is cm.

Answer 2

P=2L+2W

116=2(1+2w)+2(w)

length= 39 cm

width= 19 cm

Explanation:

Perimeter: 116 cm 116=2(1+2w)+2(w)

116=2+4w+2w

l=1+2w 114=6w

____________ w=19

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