Question

A line passes through the point (12,0) and is parallel to the line with the equation y = 1∕6x + 1. What's the equation of the line?

Answer 1

y=1/6x-6

Explanation:

The first step is to set up the equation. Since the lines are parallel the slopes will be the same.

Note: y=mx+b; m is the slope and b is the y-intercept

Since we know that the slopes are the same all we have to do is plug in (12,0) in the equation to find b (y-intercept),

0=1/6(12)+b

0=6+b

-6=b

Now that we know b all we have to do is put it in the formula y=mx+b

y=1/6x-6.

Answer 2

y = (1/6)x - 2

Explanation:

"Parallel" means "has the same slope as..." so the slope of the line you want is 1/6.

y = (1/6)x + b where b is the y-intercept (now, find it using the point (12, 0) ).

0 = (1/6)(12) + b

0 = 2 + b

b = -2

The equation is y = (1/6)x - 2