Question

If 15L of neon is at 25C is allowed to expand to 45L. What is the new temperature to maintain constant pressure?

Answer 1

`T_2=894.45K=621.30\°C`

Step-by-step explanation:

Hell there!

In this case, according to the given information, it turns out possible for us to calculate the new temperature by applying the Charles' law as a directly proportional relationship between temperature and volume:

`(V_2)/(T_2) =(V_1)/(T_1)`

Thus, we solve for the final temperature, T2, as shown below (make sure T1 is in Kelvins):

`T_2=(V_2T_1)/(V_1) \\\\T_2=((25+273.15)K*45L)/(15L)\\\\T_2=894.45K=621.30\°C`

Regards!