Question

PLEASE HELP ME WITH THIS ONE QUESTION

The frequency of violet light is 7.5 x 10^14 Hz. How much energy does a photon of violet light carry? (h = 6.626 x 10^-34 J·s; 1 eV = 1.60 x 10^-19 J)

Answer 1

The energy of a photon of violet light with a frequency of 7.5 x 10^14 Hz is 4.9695 x 10^-19 J, which is equivalent to 3.106 eV.

Step-by-step explanation:

To find the energy that a photon of violet light carries, we use the formula E = hv, where E is energy, h is Planck's constant, and v is the frequency of the light.

Given the frequency of violet light (v) is 7.5 x 10^14 Hz, and Planck's constant (h) is 6.626 x 10^-34 J·s, the energy E of a photon is calculated as follows:

E = hv = (6.626 x 10^-34 J·s)(7.5 x 10^14 Hz) = 4.9695 x 10^-19 J

To convert joules to electronvolts (eV), we use the conversion 1 eV = 1.60 x 10^-19 J. So the energy E in electronvolts is given by:

E (in eV) = 4.9695 x 10^-19 J / (1.60 x 10^-19 J/eV) = 3.106 eV

Answer 2

3.11ev

Step-by-step explanation:

`E = hf`

`E = 6.626 * 10^-^3^4 * 7.5 * 10^1^4\\E = 49.695 * 10^-^2^0`

`1ev = 1.60 * 10^-^1^9\\xev = 49.695 * 10^-^2^0 / 1.60 * 10^-^1^9\\xev = 3.1059\\xev = 3.11eV`