Question

1- The acceleration of a particle is defined by the relation a = 6 ft/s 2. Knowing

that s =-32 ft when t = 0 and v= -6 ft/s when t = 2 s, determine the velocity, the
position, and the total distance traveled when t = 5 s.
help fast​

Answer 1

The initial velocity of the particle is

v' = -6 - 6.2 = -18 ft/s

at t = 5s, the velocity is v = -18 + 6.5 = 12 ft/s

the position is

`x = - 32 - 18 * 5 + (1)/(2) * 6 * 5 {}^(2) = - 47 \: ft`

the total distance traveled is

`s = | \frac{12 {}^(2) - 18 {}^(2) }{2 * 6} | = 15 \: ft`