Question

Find the solution set of 1/3x-4≤ 2+x​

Answer 1

[-9 ≤ x] or [x ≥ -9]

Explanation:

QUESTION :-

Find the solution set of →
`(1)/(3) x - 4 \leq 2+ x`

SOLUTION :-

• Simplify the L.H.S.

`=> (x-12)/(3) \leq x + 2`

• Multiply both the sides by 3

`=> (x - 12)/(3) * 3 \leq 3(x + 2)`

`=> x - 12 \leq 3x +6`

• Substract 'x' from both the sides

`=> x - 12 - x \leq 3x + 6 -x`

`=> -12 \leq 2x + 6`

• Substract 6 from both the sides.

`=> -12 - 6 \leq 2x + 6 - 6`

`=> -18 \leq 2x`

• Divide both the sides by 2.

`=> (-18)/(2) \leq (2x)/(2)`

`=> -9 \leq x` or
`x \geq -9`

Answer 2

1/3x*3-4*3≤ 2*3+x*3

x-12≤6+3x

-12-6≤3x-x

-18/2≤2x/2

-9≤x

OR

1÷3x-4≤ 2+x

x-12≤6+3x

-12-6≤3x-x

-18/2≤2x/2

-9≤x