Answer:
A and B
x is
of y
AND
y is
of (x+y)
Explanation:
x:y is 1:3
=> y is bigger than x
=> y is 3x bigger than x
=> y = 3 lots of x
=>
![3x](https://img.qammunity.org/2022/formulas/mathematics/high-school/ng22y9jfr3fbnhxr2z5ciqamhxslnhlqcy.png)
=>
![= x](https://img.qammunity.org/2022/formulas/mathematics/high-school/4y95wvkmv8wtrt9alpbbhsplcqb4ie9wst.png)
=>
![= x](https://img.qammunity.org/2022/formulas/mathematics/high-school/4y95wvkmv8wtrt9alpbbhsplcqb4ie9wst.png)
So x is
of y
y is
of (x+y)
If x = 1 and y = 3 (substitute in values)
=> 3 is
of (4)
=> 3 is
(4)
=> 3 is (
x4)
=> 3 = 3
Therefore, y is
of (x+y) is true
So the answers are:
x is
of y
AND
y is
of (x+y)