Question

1-How many moles of NazCOs are in 10.0 ml of a 2.0 M solution?​

Answer 1

There are 20. mol of Na2CO3 in 10.0L of 2.0M solution.

Step-by-step explanation:

Molarity is represented by this equation:

(look at attachment)

In our case, we already have the molarity and volume of solution, both of which have good units.

Let's rearrange the equation to solve for the number of moles. We can do this by multiplying by L solution on both sides of the equation. The L solution will cancel out on the right side, leaving the number of moles being equal to the molarity times volume:

Moles of solute

=Lsolution×Molarity

Now we just plug the known values in!

Moles of solute = (10.0 L) (2.0M) = 20. moles

Answer 2

A solution is a mixture in which the particles are so small that the components are indistinguishable from each other. The amount of the solute and the solvent in a solution can be expressed in terms of different concentration expressions such as molarity, morality, etc.

Step-by-step explanation:

To calculate the number of moles of sodium carbonate, the volume in liters will be multiplied by the molar concentration of the solution.

moles Na2CO3 = 2.0 M x 0.0100 L = 0.020 moles Na2CO3

Hope it helps :)