Question

USE LAWS OF EXPONENT TO FIND THE VALUE OF X
㏒ ₆₄ 8=X÷2

Answer 1

x = 1

Explanation:

Using the rule of logarithms

`log_(b)` x = n ⇒ x =
`b^(n)`

Given

`log_(64)` 8 =
`(x)/(2)` , then

8 =
`64^{(x)/(2) }`

note 64 = 8² , so

8 =
`(8^2)^{(x)/(2) }` =
`8^(x)`

Since bases on both sides are equal, both 8 then equate the exponents

x = 1