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USE LAWS OF EXPONENT TO FIND THE VALUE OF X
㏒ ₆₄ 8=X÷2

1 Answer

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Answer:

x = 1

Explanation:

Using the rule of logarithms


log_(b) x = n ⇒ x =
b^(n)

Given


log_(64) 8 =
(x)/(2) , then

8 =
64^{(x)/(2) }

note 64 = 8² , so

8 =
(8^2)^{(x)/(2) } =
8^(x)

Since bases on both sides are equal, both 8 then equate the exponents

x = 1

User Theoretisch
by
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