Question

How much energy is required to convert 32g of ice at –15⁰C to liquid water at 85⁰C?

Answer 1

24.1kJ

Step-by-step explanation:

Heat capacity of water = 4200

Latent Heat of ice = 333550

Heat of Fusion = m × l = 333550 × (32/1000)kg = 10,672 = 10.672kJ

H = (m × c × change in temperature)

H = (32/1000)kg × 4200 × (85 -- 15)

H = (32/1000) × 4200 × 100

H = 13,440J = 13.44kJ

So amount of heat = 13.44kJ + 10.672kJ = 24.112kJ ~ 24.1kJ