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In ΔXYZ, ∠Y=90° and ∠X=73°. ∠ZWY=80° and XW=80. Find the length of ZY to the nearest 100th.

In ΔXYZ, ∠Y=90° and ∠X=73°. ∠ZWY=80° and XW=80. Find the length of ZY to the nearest-example-1

1 Answer

4 votes

Answer:

Solution given:

Y=90°

∠X=73°.

∠ZWY=80°

and XW=80.

ZY=?

We know that

In right angled triangle ∆ XYZ

Tan 73=
(p)/(h)

3.27=
(yz)/(xy)

3.27×[xy]=yz

xw+wy=
(yz)/(3.27)

wy=
(yz)/(3.27)-80...........(1)

again

In right angled triangle WYZ

Tan 80=
(yz)/(wy)

5.67×wy=yz

wy=
(yz)/(5.67)

yz=5.67×wy............................................(2)

Equating equation 1&2


(yz)/(5.67)=
(yz)/(3.27)-80


(yz)/(3.27)-
(yz)/(5.67)=80

5.67yz-3.27yz=80*5.67*3.27

2.4yz =1483.272

yz=
(1483.272)/(2.4)

yz=618.03

:.y=618.03unit.the length of ZY to the nearest 100th is 618.

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