Question

Can any of you help me with this? Like fast?

Branson Creek Middle School has decided to make fitness a key message to their students in the upcoming school year. As a result, they will be participating in a national fitness program. To participate, they must randomly select 15 students in the 5th grade and record their exercise time each day. The data (in minutes) are shown.

85, 80, 76, 78, 82, 88, 80, 80, 110, 85, 85, 82, 83, 88, 76

Describe the distribution of the data.
Determine the median and mean of the data.
Which measure better represents a typical value in the data set? Explain.

Answer 1

data from minimum to maximum :

76 76 78 80 80 80 82 82 83 85 85 85 88 88 110

n= 15 , so the median is X8 = 82 minutes

mean =

(76+76+78+80+80+ 80 +82+ 82+ 83+ 85+ 85+ 85 +88 +88+ 110) / 15 = (1,258)/15 = 83.87 minutes

in order to get higher standard its better use mean as a typical value.