Question

How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

Answer 1

`V_2=600mL`

Step-by-step explanation:

Hello there!

In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:

`V_2M_2=V_1M_1`

Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:

`V_2=(V_1M_1)/(M_2)\\\\ V_2=(100.0mL*18M)/(3.0M)\\\\V_2=600mL`

Regards!