Question

How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

Answer 1

Answer: A volume of 600 mL of 3.0 M
`H_(2)SO_(4)` solution can be prepared by using 100.0 mL OF 18 M
`H_(2)SO_(4)`.

Step-by-step explanation:

Given:
`V_(1)` = ?,
`M_(1) = 3.0 M\\`

`V_(2) = 100.0 mL`,
`M_(2) = 18 M`

Formula used to calculate the volume is as follows.

`M_(1)V_(1) = M_(2)V_(2)`

Substitute the values into above formula as follows.

`M_(1)V_(1) = M_(2)V_(2)\\3.0 M * V_(1) = 18 M * 100.0 mL\\V_(1) = (18 M * 100.0 mL)/(3.0M)\\= 600 mL`

Thus, we can conclude that a volume of 600 mL of 3.0 M
`H_(2)SO_(4)` solution can be prepared by using 100.0 mL OF 18 M
`H_(2)SO_(4)`.