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The [OH-] of an aqueous solution is 3.5 x 10-5. What is the [H+]?

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Final answer:

The [OH-] of an aqueous solution is 3.5 x 10-5. The [H+] can be found using the equation [H+][OH-] = 1.0 x 10-14. Simplifying the equation gives us [H+] = 1.0 x 10-14 / [OH-]. Plugging in the given value, the [H+] is 2.857 x 10-10 M.

Step-by-step explanation:

The [OH-] of an aqueous solution is 3.5 x 10-5. To find the [H+], we can use the equation [H+][OH-] = 1.0 x 10-14, which applies to any aqueous solution. Rearranging the equation gives us [H+] = 1.0 x 10-14 / [OH-]. Plugging in the given value, we have [H+] = 1.0 x 10-14 / 3.5 x 10-5.

Simplifying, we get [H+] = 2.857 x 10-10 M. Therefore, the [H+] of the given aqueous solution is 2.857 x 10-10 M.

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