Question

1. A cylinder contains600cc of ideal gas at 27°C and 650mm of pressure At constant pressure, the

volume of gas at 0°C is
(1 Point)
273cc
546cc
819cc
1365cc​

Answer 1

`546\ \text{cc}`

Step-by-step explanation:

`V_1` = Initial volume of gas = 600 cc

`V_2` = Final volume of gas

`T_1` = Initial temperature of gas =
`(27+273.15)\ \text{K}`

`T_2` = Final temperature of gas =
`(0+273.15)\ \text{K}`

We know that

`V\propto T`

So

`(V_2)/(V_1)=(T_2)/(T_1)\\\Rightarrow V_2=V_1(T_2)/(T_1)\\\Rightarrow V_2=600(0+273.15)/(27+273.15)\\\Rightarrow V_2=546\ \text{cc}`

The volume of gas at the given temperature is
`546\ \text{cc}`