Secθ= a. (sqrt tan^2 + 1) b. 1/sinθ c. (sqrt cos^2 + 1)

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asked Jun 18, 2022 112k views

2 votes

Secθ=

a. (sqrt tan^2 + 1)
b. 1/sinθ
c. (sqrt cos^2 + 1)

Mathematics
college

Ajpalma asked

by Ajpalma

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1 Answer

4 votes

Answer:

secθ=
$\sqrt{ \tan^(2) θ - 1 }$

Jax answered Jun 25, 2022

by Jax

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