Answer: 8n^6
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Work Shown:
(2n^2)^3
(2n^2)*(2n^2)*(2n^2)
(2*2*2)*(n^2*n^2*n^2)
8n^(2+2+2)
8n^6
I used the rule that a^b*a^c = a^(b+c)
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Alternative route:
(2n^2)^3
(2)^3 * (n^2)^3
8n^(2*3)
8n^6
The rules used here were (a*b)^c = (a^b)*(a^c) and (a^b)^c = a^(b*c).