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CH is an altitude of the triangle ABC, m∠A = 40°, m∠B = 68°. The circle with the diameter CH intersects sides AC and BC at points N and M respectively. Find the measure of the angles CNM, HNM, and HMN.
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CH is an altitude of the triangle ABC, m∠A = 40°, m∠B = 68°. The circle with the diameter CH intersects sides AC and BC at points N and M respectively. Find the measure of the angles CNM, HNM, and HMN.

CH is an altitude of the triangle ABC, m∠A = 40°, m∠B = 68°. The circle with the diameter-example-1
User Jessye
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Answer: CNM=65, HNM=47,HMN=43 I’m pretty sure these are right

Step by step solution: See photo
CH is an altitude of the triangle ABC, m∠A = 40°, m∠B = 68°. The circle with the diameter-example-1
User Juagicre
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