Question

I need help ASAP

For which function and interval can the extreme value theorem be applied?

f (x) = StartFraction x Over (x minus 6) squared EndFraction over the interval [3, 5]
f (x) = StartFraction negative 5 Over 2 (x minus 7) cubed EndFraction over the interval (6, 8)
f(x) = 4 tan(πx) over the interval [0, 1]
f(x) = 3ex + 1 over the interval (1, 3)

Answer 1

A

Explanation:

got it on edge!!

Answer 2

A) f(x)=x/(x-6)^2 over the interval [3, 5]

Explanation:

got it right on edge :) good luck!