Answer:
q=309.6 J
Step-by-step explanation:
Here we'll be using the formula of specific heat capacity: Q=mcΔT
Q= heat (joules)
m=mass (g)
c=specific heat capacity
ΔT= change in temperature > Final temp. - initial temp.
Let's plug in what we know and solve for q=heat.
q=(20)(0.387)(50-10)
q=(20)(0.387)(40)
q=309.6 joules
Depending on your teacher and the problem, they might want you to keep the temperature in C. Mine wanted them all in Kelvin, so if we were to convert it to Kelvin it would be:
273 + 40= 313 K
q=(20)(0.387)(313)
q=2422.6 J