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The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 10.9 degrees. If skyscraper B is 1425 feet​ tall, how far apart are the two​ skyscrapers? Assume the bases of the two buildings are at the same elevation.

User Melena
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1 Answer

4 votes

Answer:

269.46

Explanation:

sin(theta) = opposite / adjacent

adjacent = opposite / sin(theta)

adjacent = 1425*sin(10.9)

adjacent = 269.4610063

User Chrisdowney
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