Answer:
51.1 g NH3
The required chemical reaction is given by:
N2 + 3H2 --> 2NH3
4.5 mol H2 × (2 mol NH3/3 mol H2) = 3 mol NH3
molar mass of NH3 is 17.031 g/mol
3 mol NH3 × (17.031 g NH3/1 mol NH3) = 51.1 g NH3
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