Answer:
The dimensions of the rectangle are:
2a^2b^2 and 3ab^2 + 5a + 7b
Explanation:
The question is asking for the length and width of the rectangle, and gives you an equation that shows the area of the rectangle. It says to factor out the GCF to find these dimensions. In simpler terms, the question wants you to divide the equation for the area, 6^3b^4 + 14a^2b^3 + 10a^3b^2, into two different equations for the length and width, which can't be divided more.
We have three terms to find the greatest common factor (GCF) of. 6^3b^4, 14a^2b^3, and 10a^3b^2. First, let's factor out the 2. This leaves us with
2(3^3b^4 + 7a^2b^3 + 5a^3b^2)
It seems like we're done with factoring out coefficients, for 3, 5, and 7 are all prime. Now, variables. Each term has a factor of a^2b^2. (not more, for this is the limit of 14a^2b^2.)
2a^2b^2(3ab^2 + 7b + 5a) . (this is the same as the answer above, but I changed the order of 7b and 5a there because some online things are specific and don't like it if you don't put the equations in order.)
And that's it!