Question

How many moles of NH3 are produced when 0.45 moles of H2 gas react

with N2 gas? N2 + 3H2 -->2 NH3 (mole to mole conversion)

Answer 1

`\boxed {\boxed {\sf 0.3 \ mol \ NH_3}}`

Step-by-step explanation:

We need to use stiochiometry and a mole to mole conversion to solve this problem.

First, examine the chemical equation. Make sure it is balanced before doing any calculations.

`N_2+3H_2 \rightarrow 2NH_3`

It is balanced, so we can also use the coefficients to refer to molar amounts.

So, the equation is also saying that 1 mole of N₂ (no coefficient implies 1) and 3 moles of H₂ react to form 2 moles of NH₃.

`1 \ mol \ N_2 + 3 \ mol \ H_2 \rightarrow 2 \ mol \ NH_3`

Now we can use this information to make a ratio. We know that we have 0.45 moles of hydrogen, and we are trying to find the moles of ammonia.

According to the original equation, 3 moles of hydrogen produce 2 moles of ammonia. Let's make a ratio.

`\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}`

We have 0.45 moles of hydrogen, so multiply by that number.

`0.45 \ mol \ H_2 *\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}`

Flip the ratio so the units of moles of hydrogen cancel.

`0.45 \ mol \ H_2 *(2 \ mol \ NH_3 )/(3 \ mol \ H_2)`

`0.45 *(2 \ mol \ NH_3 )/(3)`

`\frac {0.45 *2 \ }{3} mol \ NH_3`

`\frac {0.9 \ }{3} mol \ NH_3`

`0.3 \ mol \ NH_3`

0.3 moles of ammonia are produced when 0.45 moles of hydrogen gas react with nitrogen gas.