Question

What is the average rate of change of h over the interval {1,2}?

Answer 1

3

Explanation:

The average rate of change of h(x) in the closed interval [ a, b ] is

`(h(b)-h(a))/(b-a)`

Here [ a, b ] = [ 1, 2 ] , then

h(b) = h(2) = 0 ← from table for x = 2

h(a) = h(1) = - 3 ← from table for x = 1 , then

average rate of change =
`(0-(-3))/(2-1)` =
`(0+3)/(1)` = 3